To calculate the experimental percentage of water in the hydrate, we can use the following formula:

% Water = [(Mass of hydrate - Mass of anhydrous compound) / Mass of hydrate] x 100

Given:

Mass of hydrate (ac xH2O) = 1.632 g

Mass of anhydrous compound (AC) = 1.008 g

Substituting these values into the formula, we get:

% Water = [(1.632 g - 1.008 g) / 1.632 g] x 100

% Water = (0.624 g / 1.632 g) x 100

% Water ≈ 38.2%

Therefore, the experimental percentage of water in the hydrate is approximately 38.2%.