To balance the chemical equation between Boron and water (H2O), we need to make sure that the numbers of atoms of each element are the same on both sides of the equation. The reaction between Boron and H2O produces Boric acid (H3BO3) and Hydrogen gas (H2). Here's the balanced chemical equation:

```

4B(s) + 6H2O(l) -> 2H3BO3(aq) + 3H2(g)

```

- On the left side of the equation, we have four Boron atoms (4B) and 6 H2O molecules (6H2O).

- On the right side, we have the product side with two H3BO3 molecules (2H3BO3) and three H2 molecules (3H2).

In this balanced equation, we have:

- 4 Boron atoms on both sides.

- 12 Hydrogen atoms on both sides.

- 6 Oxygen atoms on both sides.