Molarity (M) = Moles of Solute (mol) / Volume of Solution (L)
Rearranging the formula to solve for moles of solute:
Moles of Solute (mol) = Molarity (M) * Volume of Solution (L)
Substituting the given values:
Moles of HNO3 = 2.0 M * 5.0 L = 10 moles
Therefore, 10 moles of HNO3 are needed to prepare 5.0 liters of a 2.0 M solution of HNO3.