When iron and copper sulfate react, a displacement reaction occurs. Iron is more reactive than copper, so it will replace copper in the compound. The products of the reaction will be iron sulfate and copper metal.

The reaction can be represented by the following equation:

```

Fe + CuSO4 -> FeSO4 + Cu

```

In this equation, Fe represents iron, CuSO4 represents copper sulfate, FeSO4 represents iron sulfate, and Cu represents copper metal.

The reaction will occur when the two reactants are in contact with each other. The iron atoms will collide with the copper sulfate molecules, and the iron atoms will displace the copper atoms from the compound. The copper atoms will then be deposited on the surface of the iron.

The reaction will continue until all of the iron atoms have been reacted. The amount of copper that is produced will be equal to the amount of iron that was used.

The reaction between iron and copper sulfate is an example of a redox reaction. In a redox reaction, one substance is oxidized and another substance is reduced. In this case, the iron is oxidized and the copper is reduced.

The oxidation of iron can be represented by the following equation:

```

Fe -> Fe2+ + 2e-

```

In this equation, Fe represents iron, Fe2+ represents ferrous iron, and e- represents an electron.

The reduction of copper can be represented by the following equation:

```

Cu2+ + 2e- -> Cu

```

In this equation, Cu2+ represents copper, Cu represents copper metal, and e- represents an electron.