Step 1: Calculate moles of NaOH used in the titration
Moles of NaOH = Concentration of NaOH × Volume of NaOH used
Moles of NaOH = 0.108 M × 31.43 mL / 1000 mL/L
Moles of NaOH = 0.0033846 moles
Step 2: Determine moles of acetic acid
Since the reaction between NaOH and acetic acid is a 1:1 stoichiometry, the moles of acetic acid are equal to the moles of NaOH used in the titration.
Moles of acetic acid = 0.0033846 moles
Step 3: Calculate mass of acetic acid
Molar mass of acetic acid (CH3COOH) = 60.05 g/mol
Mass of acetic acid = Moles of acetic acid × Molar mass of acetic acid
Mass of acetic acid = 0.0033846 moles × 60.05 g/mol
Mass of acetic acid = 0.2031 grams
Step 4: Calculate percentage of acetic acid in vinegar
Percentage of acetic acid = (Mass of acetic acid / Mass of vinegar) × 100%
Percentage of acetic acid = (0.2031 g / 4.441 g) × 100%
Percentage of acetic acid = 4.572 %
Therefore, the vinegar sample contains 4.572% acetic acid.