pH = -log[H+]
and
[H+][OH-] = Kw
where Kw is the ion product constant for water (Kw = 1.0 x 10^-14 at 25°C).
First, we calculate the hydrogen ion concentration ([H+]) using the given pH:
[H+] = 10^(-pH)
[H+] = 10^(-12.40)
[H+] = 3.98 x 10^-13 M
Next, we use the relationship [H+][OH-] = Kw to calculate [OH-]:
[OH-] = Kw/[H+]
[OH-] = (1.0 x 10^-14)/(3.98 x 10^-13)
[OH-] = 2.51 x 10^-2 M
Therefore, the hydroxide ion concentration of the solution is 2.51 x 10^-2 M.