The reaction can be represented as follows:
C₂H₄ + Br₂ → C₂H₄Br₂
In this reaction, the double bond between the two carbon atoms in ethene is broken, and each carbon atom forms a bond with a bromine atom. The product of the reaction is 1,2-dibromoethane (C₂H₄Br₂), which is a colorless liquid with a sweet odor.
The reaction between ethene and bromine water is a rapid and exothermic process, meaning that it releases heat. The bromine water turns from its original orange color to a colorless solution as the reaction proceeds. This color change can be used as an indicator to detect the presence of double bonds in unsaturated hydrocarbons like ethene.