$$PV = nRT$$
where:
* \(P\) is the pressure of the gas
* \(V\) is the volume of the gas
* \(n\) is the number of moles of gas
* \(R\) is the ideal gas constant
* \(T\) is the temperature of the gas
We are given the following information:
* \(P = 1.2 ATM\)
* \(V = 31 liters\)
* \(T = 87 c = 360 k\)
We can use the ideal gas constant in units of L * ATM / (mol * K) which equals: 0.08206
Substituting these values into the ideal gas law, we get:
$$1.2 ATM * 31 liters = n * 0.08206 L * ATM / (mol * K) * 360 k$$
Solving for \(n\), we get:
$$n = 1.03 moles$$
Therefore, we have 1.03 moles of gas.
