$$ Moles \ of \ Al = \frac{Mass \ of \ Al \ (kg)}{Molar \ Mass \ of \ Al \ (g/mol)} \times \frac{1000 \ g}{1 \ kg} $$
$$ Moles \ of \ Al = \frac{62.13 \ kg}{26.98 \ g/mol} \times \frac{1000 \ g}{1 \ kg} $$
$$ Moles \ of \ Al = 2306.14 \ moles $$
Therefore, 62.13 kg of Al is equal to 2306.14 moles of Al.