To calculate the number of molecules in 6.32 mg of CCl₄, we first need to convert the mass to moles:
$$n = \frac{m}{M}$$
$$= \frac{6.32 \times 10^{-3} g}{153.82 g/mol}$$
$$= 4.105 \times 10^{-5} mol$$
We then use Avogadro's number (6.022 × 10^23 molecules/mol) to convert moles to molecules:
$$N = nN_A$$
$$= 4.105 \times 10^{-5} mol \times 6.022 \times 10^{23} molecules/mol$$
$$= 2.476 \times 10^{19} molecules$$
Therefore, there are 2.476 × 10^19 molecules of carbon tetrachloride in 6.32 mg of that compound.
