Step 1: Calculate the moles of Mn and S in the compound.
- Moles of Mn = (mass of Mn) / (molar mass of Mn)
= (mass of Mn in the oxide - mass of Mn in the sample) / (molar mass of Mn)
= (1.22 g - 0.5 g) / (54.94 g/mol)
= 0.0134 mol
- Moles of S = (mass of S) / (molar mass of S)
= (mass of S in the oxide - mass of S in the sample) / (molar mass of S)
= (1.38 g - 0.5 g) / (32.06 g/mol)
= 0.0274 mol
Step 2: Determine the mole ratio of Mn and S.
- Divide the moles of each element by the smaller number of moles to obtain the simplest whole-number ratio.
- Mn: S = 0.0134 mol / 0.0134 mol : 0.0274 mol / 0.0134 mol
- Mn: S = 1 : 2
Step 3: Write the empirical formula.
- The simplest formula of the compound is MnS, as the mole ratio of Mn to S is 1:2.