$$A = \frac{m}{\rho t}$$

Where:

* A is the area in square meters (m2)

* m is the mass of the foil in kilograms (kg)

* ρ is the density of the foil in kilograms per cubic meter (kg/m3)

* t is the thickness of the foil in meters (m)

Substituting the given values into the equation:

$$A = \frac{0.495 \text{ g}}{2.70 \text{ g/cm}^3 \times 29647 \times 10^{-9} \text{ m}} = 6.81 \times 10^{-3} \text{ m}^2$$

Therefore, the area of the foil is 6.81 x 10^-3 square meters.