In this case, we have 0.1 moles of HCl (a strong acid) and 0.2 moles of NaOH (a strong base). When these two substances react, they will undergo a neutralization reaction, resulting in the formation of water and a salt (NaCl).
HCl + NaOH -> NaCl + H2O
Since HCl is a strong acid, it will completely dissociate in water, releasing H+ ions. NaOH, being a strong base, will completely dissociate in water, releasing OH- ions. The resulting solution will contain a high concentration of either H+ or OH- ions, depending on the excess reactant.
Therefore, the mixture of 0.1 moles of HCl and 0.2 moles of NaOH will not form a buffer because it lacks a weak acid-conjugate base or weak base-conjugate acid pair that is necessary for buffering action. Instead, the solution will likely be acidic due to the excess H+ ions from the HCl.