$$ 2 Na_{(s)} + Br_{2(l)} \longrightarrow 2NaBr_{(s)}$$
This reaction is an example of a redox reaction, where there is a transfer of electrons between the reactants. In this case, sodium donates electrons to bromine, reducing it from Br2 to 2Br-. This results in the formation of the ionic compound sodium bromide (NaBr).