To determine the volume occupied by 15.7 g of calcium chloride (CaCl2), we need to know its density. The density of CaCl2 is 2.15 g/cm³.

Density = mass/volume

Volume = mass/density

Substituting the given values:

Volume = 15.7 g / 2.15 g/cm³

Volume ≈ 7.3 cm³

Therefore, 15.7 g of calcium chloride would occupy a volume of approximately 7.3 cm³.