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  • Sodium Ions in NaCl: Calculation & Explanation
    The answer: 1.80 x 10^24

    Explanations:

    Each molecule of NaCl contains one sodium ion and one chloride ion. Therefore, 3.0 moles of NaCl contains 3.0 moles of sodium ions.

    $$(3.0 \text{ mol NaCl})(6.022 \times 10^{23} \text{ Na}^+ \text{ ions/mol NaCl}) = 1.81 \times 10^{24} \text{ Na}^+ \text{ ions}$$

    Therefore, there are 1.81 x 10^24 sodium ions in 3.0 moles of NaCl.

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