The dot product of two methanol molecules is given by the following equation:
$$\vec{A} \cdot \vec{B} = \Vert \vec{A} \Vert \Vert \vec{B} \Vert \cos \theta$$
where \(\vec{A}\) and \(\vec{B}\) are the two methanol vectors, \(\Vert \vec{A} \Vert\) and \(\Vert \vec{B} \Vert\) are their magnitudes, and \(\theta\) is the angle between them.
The cross product of two methanol molecules is given by the following equation:
$$\vec{A} \times \vec{B} = \Vert \vec{A} \Vert \Vert \vec{B} \Vert \sin \theta \hat{n}$$
where \(\vec{A}\) and \(\vec{B}\) are the two methanol vectors, \(\Vert \vec{A} \Vert\) and \(\Vert \vec{B} \Vert\) are their magnitudes, \(\theta\) is the angle between them, and \(\hat{n}\) is the unit vector perpendicular to both \(\vec{A}\) and \(\vec{B}\).