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  • Calcium Chloride (CaCl2) Molar Solution: Ions & Atoms Calculation
    To determine the number of ions or atoms of calcium and chloride in 1.5 moles of CaCl2, we need to consider the chemical formula and Avogadro's number.

    1. Calcium (Ca) ions:

    - Each formula unit of CaCl2 contains one calcium (Ca) ion.

    - In 1.5 moles of CaCl2, there are 1.5 moles of Ca ions.

    - Avogadro's number tells us that 1 mole of any substance contains 6.022 × 10^23 particles (atoms, ions, or molecules).

    - Therefore, 1.5 moles of CaCl2 contain 1.5 moles × 6.022 × 10^23 particles/mole = 9.033 × 10^23 Ca ions.

    2. Chloride (Cl) ions:

    - Each formula unit of CaCl2 contains two chloride (Cl) ions.

    - In 1.5 moles of CaCl2, there are 1.5 moles of Cl ions (since each CaCl2 molecule contributes two Cl ions).

    - Therefore, 1.5 moles of CaCl2 contain 1.5 moles × 6.022 × 10^23 particles/mole = 9.033 × 10^23 Cl ions.

    So, in 1.5 moles of CaCl2, there are 9.033 × 10^23 calcium ions (Ca^2+) and 9.033 × 10^23 chloride ions (Cl^-).

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