Let the oxidation number of Br be x.
The overall charge of BrO3- is -1.
The oxidation number of oxygen is -2.
There are three oxygen atoms in BrO3-.
So, the total oxidation number contributed by oxygen is 3 × (-2) = -6.
Therefore, the oxidation number of Br (x) can be calculated as follows:
x + (-6) = -1
x = -1 + 6
x = +5
Hence, the oxidation number of Br in BrO3- is +5.