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  • Calculating Atoms in Carbon Monoxide: A Step-by-Step Guide
    To calculate the number of atoms in 63.5 g of carbon monoxide, we need to use Avogadro's number and the molar mass of carbon monoxide.

    The molar mass of carbon monoxide (CO) is 28.01 g/mol. This means that one mole of carbon monoxide weighs 28.01 grams.

    Avogadro's number is 6.022 x 10^23. This means that one mole of any substance contains 6.022 x 10^23 atoms (or molecules).

    So, to calculate the number of atoms in 63.5 g of carbon monoxide, we can use the following formula:

    Number of atoms = (Mass in grams) / (Molar mass in g/mol) * Avogadro's number

    Substituting the given values into the formula, we get:

    Number of atoms = (63.5 g) / (28.01 g/mol) * (6.022 x 10^23 atoms/mol)

    Number of atoms = 1.43 x 10^24 atoms

    Therefore, there are 1.43 x 10^24 atoms in 63.5 g of carbon monoxide.

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