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  • Oxygen Production from Potassium Chlorate: A Stoichiometric Calculation
    6 moles of oxygen

    Explanation:

    The balanced chemical equation for the decomposition of potassium chlorate is:

    $$2KClO_3 \rightarrow 2KCl + 3O_2$$

    This means that for every 2 moles of potassium chlorate that decompose, 3 moles of oxygen are produced. Therefore, 12 moles of potassium chlorate will produce:

    $$12 \ \text{mol KClO}_3 \ \times \frac{3 \ \text{mol O}_2}{2 \ \text{mol KClO}_3} = 18 \ \text{mol O}_2$$

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