1. Calculate the amount of NaOH needed.

$$Molarity = \frac{Moles\ of\ NaOH}{Liters\ of\ Solution}$$

Rearranging the formula to solve for moles of NaOH:

$$Moles \ of \ NaOH \ = Molarity \times Liters\ of\ Solution$$

$$Moles \ of \ NaOH =0.02 \ M \times 1 \ L= 0.002 \ mol\ NaOH$$

2. Weigh out the required amount of NaOH.

The molecular weight of NaOH is approximately 40 g/mol. To get 0.002 moles of NaOH in grams:

$$Mass \ of \ NaOH \ = Moles\ of\ NaOH \times Molecular\ Weight $$

$$Mass \ of \ NaOH \ = 0.002 \ mol \times 40 \ g/mol = 0.08 \ g$$

3. Dissolve the NaOH in a small amount of water.

Carefully add 0.08 g of NaOH to approximately 100 mL of distilled water in a beaker. Stir until the NaOH is completely dissolved.

4. Transfer the solution to a 1-liter volumetric flask

Use a graduated cylinder to transfer the NaOH solution to a 1-liter volumetric flask. Rinse the beaker with a small amount of distilled water and add it to the flask.

5. Fill the flask to the 1-liter mark with distilled water.

Add distilled water to the flask until the level reaches the 1-liter mark. Swirl the flask gently to mix the solution.

6. Mix the solution thoroughly.

Cap the volumetric flask and invert it several times to ensure the solution is well-mixed.

Now you have 1 liter of 0.02M NaOH solution. Store the solution in a clean, labeled bottle at room temperature.

Remember to wear appropriate safety gear, including gloves and eye protection, when handling NaOH. NaOH is a corrosive substance and can cause severe burns and injuries if not handled with care.