To calculate the final mass of the anhydrous cupric sulfate, we need to know the initial mass of the hydrated cupric sulfate and the percentage of water present in it.

Let's assume that the initial mass of the hydrated cupric sulfate is 100 grams and the percentage of water present in it is 25%.

Mass of water in the hydrated cupric sulfate = 100 grams * 25% = 25 grams

Mass of anhydrous cupric sulfate in the hydrated cupric sulfate = 100 grams - 25 grams = 75 grams

Since we are converting hydrated cupric sulfate to anhydrous cupric sulfate, we need to remove the water molecules from the hydrated cupric sulfate. This means that the final mass of the anhydrous cupric sulfate will be less than the initial mass of the hydrated cupric sulfate.

Therefore, the final mass of the anhydrous cupric sulfate will be 75 grams.