N2 + 3H2 -> 2NH3
From the equation, we can see that 3 moles of H2 are required to produce 2 moles of NH3. Therefore, if we have 1.4 moles of H2, we can calculate the moles of NH3 produced using the following ratio:
(2 moles NH3 / 3 moles H2) x (1.4 moles H2) = 0.933 moles NH3
So, 0.933 moles of NH3 are produced when 1.4 moles of H2 react.