The reaction between Na3PO4 and KOH is a double displacement reaction. In a double displacement reaction, two reactants exchange ions to form two new products. In this case, the sodium ions (Na+) from Na3PO4 and the potassium ions (K+) from KOH exchange places, forming NaOH and K3PO4.

The balanced chemical equation for this reaction is:

Na3PO4 + 3KOH → 3NaOH + K3PO4