The molecular weight of ferrous ascorbate is approximately 198.11 g/mol, and the molecular weight of elemental iron is 55.845 g/mol. Ferrous ascorbate contains 1 iron atom per molecule, so 198.11 g of ferrous ascorbate contains 55.845 g of elemental iron.
Therefore, to find the amount of ferrous ascorbate equivalent to 100 mg of elemental iron, we can set up a proportion:
```
198.11 g ferrous ascorbate / 55.845 g elemental iron = x g ferrous ascorbate / 100 mg elemental iron
```
Solving for x, we get:
```
x = (100 mg elemental iron * 198.11 g ferrous ascorbate) / 55.845 g elemental iron
x ≈ 354.48 mg ferrous ascorbate
```
Therefore, approximately 354.48 mg of ferrous ascorbate is equivalent to 100 mg of elemental iron.