To calculate the molarity (M) of a 0.050 N H2SO4 solution, we need to consider that H2SO4 is a diprotic acid, meaning it can donate two hydrogen ions (H+) per molecule.

The relationship between normality (N) and molarity (M) for an acid is given by:

M = N × Number of dissociable hydrogen ions

So, for H2SO4:

M = 0.050 N × 2 (since H2SO4 can donate 2 H+ ions)

M = 0.100 M

Therefore, the molarity of the 0.050 N H2SO4 solution is 0.100 M.