• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Calculating the Oxidation Number of Carbon in Glucose (C6H12O6)
    The oxidation number of carbon (C) in glucose (C6H12O6) can be determined using the following rules:

    1. The oxidation number of oxygen (O) is usually -2.

    2. The oxidation number of hydrogen (H) is usually +1.

    3. The sum of the oxidation numbers of all atoms in a neutral compound is zero.

    Considering glucose (C6H12O6), we can assign the oxidation numbers as follows:

    - Let the oxidation number of carbon (C) be "x".

    - There are six carbon atoms, so the total oxidation number from carbon is 6x.

    - There are twelve hydrogen atoms, each with an oxidation number of +1, so the total oxidation number from hydrogen is +12.

    - There are six oxygen atoms, each with an oxidation number of -2, so the total oxidation number from oxygen is -12.

    According to the third rule, the sum of the oxidation numbers must be zero:

    6x + 12(+1) + 6(-2) = 0

    Simplifying the equation:

    6x + 12 - 12 = 0

    6x = 0

    Solving for x, we find:

    x = 0

    Therefore, the oxidation number of carbon (C) in glucose is 0.

    Science Discoveries © www.scienceaq.com