To calculate the amount of NaOH present in one liter of 50% purity NaOH liquid with a density of 1.53 g/mL, we can use the formula:

Mass of NaOH = Volume of solution (in liters) × Density (in g/mL) × Percentage purity

Let's substitute the given values into the formula:

Mass of NaOH = 1 L × 1.53 g/mL × 50% = 76.5 g

Therefore, there are 76.5 grams of NaOH present in one liter of 50% purity NaOH liquid with a density of 1.53 g/mL.