1. Assign the oxidation state of hydrogen as +1.
2. Assign the oxidation state of oxygen as -2.
3. Let the oxidation state of N be \(x\).
4. Set up the equation: +1 + x + 2(-2) = 0.
5. Solve for x: +1 + x - 4 = 0, x = +3.
Therefore, the oxidation state of N in \(HNO_2\) is +3.