To draw the Lewis structure of CH3COH, we need to first determine the total number of valence electrons in the molecule. Carbon has four valence electrons, hydrogen has one valence electron, and oxygen has six valence electrons. The total number of valence electrons in CH3COH is therefore:

$$\text{Total valence electrons} = (4 \times 1) + (3 \times 1) + (1 \times 6) = 14$$

Next, we need to connect the atoms together with single bonds. We start by connecting the carbon atom to the three hydrogen atoms and the oxygen atom. This gives us the following structure:

```

H H H

| | |

C - O - H

|

H

```

We then add lone pairs of electrons to each atom so that each atom has a complete octet of electrons. This gives us the following Lewis structure:

```

H H H

| | |

C - O - H

| |

H :

```

In this Lewis structure, the carbon atom has four bonds (three single bonds and one double bond) and has a complete octet of electrons. The oxygen atom has two bonds (one single bond and one double bond) and has a complete octet of electrons. The hydrogen atoms each have one bond and a complete duet of electrons.