1. Start with the chemical formula of lithium oxalate: Li2C2O4.
2. Calculate the molar mass of Li2C2O4 by adding the atomic masses of its constituent atoms.
- Li: 2 x 6.941 g/mol = 13.882 g/mol
- C: 2 x 12.011 g/mol = 24.022 g/mol
- O: 4 x 15.999 g/mol = 63.996 g/mol
Total molar mass of Li2C2O4 = 13.882 g/mol + 24.022 g/mol + 63.996 g/mol = 101.900 g/mol.
3. Avogadro's number is approximately 6.022 x 10^23, which represents the number of particles (atoms, molecules, or ions) present in one mole of a substance.
4. To determine the number of individual oxygen atoms in one mole of Li2C2O4, multiply the Avogadro's number by the number of oxygen atoms present in the formula.
There are four oxygen atoms in one molecule of Li2C2O4. Therefore, in one mole of Li2C2O4, there are:
4 oxygen atoms/molecule * 6.022 x 10^23 molecules/mole = 2.4088 x 10^24 oxygen atoms.
In conclusion, one mole of Li2C2O4 contains 2.4088 x 10^24 individual oxygen atoms.
