Given :
Mass of the mixture = 17 grams
Moles of the mixture = 0.8 moles
1. Molar mass of the mixture
Molar mass = (Mass of the mixture) / (Moles of the mixture)
Molar mass = 17 / 0.8
Molar mass = 21.25 g/mol
2. Number of moles of CH4 in the mixture
Let's assume that the number of moles of CH4 in the mixture is x moles. Then, the number of moles of NO in the mixture is (0.8 - x) moles.
Mass of CH4 = (Number of moles of CH4) × (Molar mass of CH4)
Mass of CH4 = x × 16 g/mol
Mass of NO = (Number of moles of NO) × (Molar mass of NO)
Mass of NO = (0.8 - x) × 30 g/mol
The total mass of the mixture is the sum of the masses of CH4 and NO.
17 = 16x + 30(0.8 -x)
= 16x+ 24 - 30x
= -14x + 24 =0
= 14x =24
= x= 24/14
x = 1.714 moles.
_Therefore, the number of moles of CH4 in the mixture is 1.714 moles, which is greater than 0.8 moles._
3. Mass of CH4 in the mixture
Mass of CH4 = (Number of moles of CH4) × (Molar mass of CH4)
Mass of CH4 = 1.714 × 16 g/mol
Mass of CH4 = 27.424 grams .
Therefore, the mass of CH4 in the mixture is 27.424 grams, which is greater than 8 grams.
4. Number of moles of NO in the mix is
Number of moles of NO = (0.8 - x)
= 0.8 - 1.714
= -0.914
_NO moles are negative, which means it's not physically possible_.
