To determine the moles of PbCl₂ produced when 14 moles of AlCl₃ are consumed, we need to consider the balanced chemical equation for the reaction between aluminum chloride (AlCl₃) and lead (Pb):

2AlCl₃ + 3Pb → 2Al + 3PbCl₂

From the balanced equation, we can see that for every 2 moles of AlCl₃ consumed, 3 moles of PbCl₂ are produced.

Therefore, if 14 moles of AlCl₃ are consumed, the number of moles of PbCl₂ produced can be calculated as follows:

Moles of PbCl₂ produced = (14 moles AlCl₃) × (3 moles PbCl₂ / 2 moles AlCl₃)

Moles of PbCl₂ produced = 21 moles PbCl₂

Hence, if 14 moles of AlCl₃ are consumed, 21 moles of PbCl₂ are produced.