$$12.01 \text{ g/mol} + 4(35.45 \text{ g/mol}) = 153.82 \text{ g/mol}$$

So, the number of moles of CCl4 in 22.5 g is:

$$n = \frac{m}{M} = \frac{22.5 \text{ g}}{153.82 \text{ g/mol}} = 0.146 \text{ mol}$$

Therefore, there are 0.146 moles of CCl4 in 22.5 g of the compound.