1. Convert the percentages to grams assuming a 100g sample:
- Carbon: 22 g
- Hydrogen: 4.6 g
- Bromine: 73.4 g
2. Convert the grams of each element to moles:
- Carbon: 22 g / 12.01 g/mol = 1.83 mol
- Hydrogen: 4.6 g / 1.008 g/mol = 4.57 mol
- Bromine: 73.4 g / 79.90 g/mol = 0.921 mol
3. Divide each mole value by the smallest mole value to get the simplest whole number ratio:
- Carbon: 1.83 mol / 0.921 mol ≈ 2
- Hydrogen: 4.57 mol / 0.921 mol ≈ 5
- Bromine: 0.921 mol / 0.921 mol = 1
4. Write the empirical formula using the whole number ratio:
C2H5Br
Therefore, the empirical formula of the compound is C2H5Br.