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  • Calculate Empirical Formula: 22% Carbon, 4.6% Hydrogen, 73.4% Bromine
    To determine the empirical formula of a compound with the given elemental composition, we need to find the simplest whole number ratio of the elements present.

    1. Convert the percentages to grams assuming a 100g sample:

    - Carbon: 22 g

    - Hydrogen: 4.6 g

    - Bromine: 73.4 g

    2. Convert the grams of each element to moles:

    - Carbon: 22 g / 12.01 g/mol = 1.83 mol

    - Hydrogen: 4.6 g / 1.008 g/mol = 4.57 mol

    - Bromine: 73.4 g / 79.90 g/mol = 0.921 mol

    3. Divide each mole value by the smallest mole value to get the simplest whole number ratio:

    - Carbon: 1.83 mol / 0.921 mol ≈ 2

    - Hydrogen: 4.57 mol / 0.921 mol ≈ 5

    - Bromine: 0.921 mol / 0.921 mol = 1

    4. Write the empirical formula using the whole number ratio:

    C2H5Br

    Therefore, the empirical formula of the compound is C2H5Br.

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