To calculate the total number of atoms in 14.5 g of sodium acetate (CH3COONa), we need to determine the molar mass of sodium acetate and use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the mass into the number of atoms.

1. Calculate the molar mass of sodium acetate:

- Molar mass of Na = 22.99 g/mol

- Molar mass of C = 12.01 g/mol

- Molar mass of H = 1.008 g/mol

- Molar mass of O = 16.00 g/mol

Molar mass of CH3COONa = (22.99 g/mol) + (3 x 12.01 g/mol) + (3 x 1.008 g/mol) + (3 x 16.00 g/mol)

= 82.03 g/mol

2. Calculate the number of moles in 14.5 g of sodium acetate:

Number of moles = Mass / Molar mass

= 14.5 g / 82.03 g/mol

= 0.1767 mol

3. Determine the total number of atoms:

Since there is one sodium atom, three carbon atoms, three hydrogen atoms, and three oxygen atoms in each molecule of sodium acetate, we can multiply the number of moles by the total number of atoms per molecule.

Total number of atoms = (Number of moles) x (Total atoms per molecule)

= 0.1767 mol x (1 Na + 3 C + 3 H + 3 O)

= 0.1767 mol x (1 + 3 + 3 + 3)

= 0.1767 mol x 10

= 1.767 x 10^23 atoms

Therefore, the total number of atoms in 14.5 g of sodium acetate is approximately 1.767 x 10^23 atoms.