1. Energy content of glucose:
One molecule of glucose contains approximately 2870 kilojoules per mole (kJ/mol) of energy stored in its chemical bonds.
2. Energy content of ATP:
Each ATP molecule contains approximately 30.5 kJ/mol of energy in its high-energy phosphate bonds.
3. Number of generated ATP molecules:
Given that the cell generates 32 ATP molecules per molecule of glucose.
4. Total energy yielded by ATP:
The total energy yielded by the 32 ATP molecules is:
32 ATP molecules x 30.5 kJ/mol = 976 kJ/mol
5. Efficiency of cellular respiration:
The efficiency of cellular respiration is calculated by dividing the total energy yielded by ATP by the energy content of glucose and expressed as a percentage:
Efficiency = (Total energy yielded by ATP / Energy content of glucose) x 100
Efficiency = (976 kJ/mol / 2870 kJ/mol) x 100 = 33.97%
Therefore, the efficiency of cellular respiration in this scenario, when the cell generates 32 ATP molecules per molecule of glucose, is approximately 34%.
