λmax = b / T
Where:
* λmax is the wavelength of maximum radiation (in meters)
* b is Wien's displacement constant, approximately 2.898 × 10-3 m·K
* T is the temperature of the star (in Kelvin)
Let's plug in the given temperature:
* λmax = (2.898 × 10-3 m·K) / (36000 K)
* λmax ≈ 8.05 × 10-8 m
Converting this to nanometers (nm):
* λmax ≈ 80.5 nm
Therefore, a star with a surface temperature of 36,000 K will radiate the most energy at a wavelength of approximately 80.5 nanometers. This wavelength falls within the extreme ultraviolet (EUV) range of the electromagnetic spectrum.