λmax * T = b
where:
* λmax is the wavelength at which the star emits the most light (in meters)
* T is the star's surface temperature (in Kelvin)
* b is Wien's displacement constant, approximately 2.898 × 10-3 m·K
1. Convert the wavelength to meters:
* 290 nm = 290 × 10-9 m
2. Rearrange the equation to solve for T:
* T = b / λmax
3. Plug in the values and solve:
* T = (2.898 × 10-3 m·K) / (290 × 10-9 m)
* T ≈ 9993 K
Therefore, the temperature of a star whose maximum light is emitted at a wavelength of 290 nm is approximately 9993 Kelvin.