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  • Calculating Orbital Period: Object at 65 AU from the Sun
    Here's how to approximate the orbital period of an object at 65 AU from the Sun using Kepler's Third Law:

    Kepler's Third Law

    Kepler's Third Law states that the square of the orbital period (P) of a planet is proportional to the cube of the semi-major axis (a) of its orbit. Mathematically:

    P² = a³

    Where:

    * P is the orbital period in years

    * a is the semi-major axis in astronomical units (AU)

    Calculation

    1. Plug in the distance: We know the object is 65 AU from the Sun. Assuming a circular orbit (which is a simplification), this is our semi-major axis (a = 65 AU).

    2. Solve for P:

    * P² = (65 AU)³

    * P² = 274,625

    * P = √274,625 ≈ 524 years

    Approximate Orbital Period

    Therefore, an object orbiting the Sun at a distance of 65 AU would have an approximate orbital period of around 524 years.

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