Here's how to calculate it:
1. Kepler's Third Law Formula:
T² = a³
Where:
* T is the orbital period in Earth years
* a is the average distance from the Sun in Astronomical Units (AU)
2. Plug in the Values:
* a = 10 AU
3. Solve for T:
T² = 10³
T² = 1000
T = √1000
T ≈ 31.62 years
Therefore, the period of a planet with a solar distance of 10 AU is approximately 31.62 years.