Kepler's Third Law:
The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.
* P² = a³
Where:
* P is the orbital period in years
* a is the semi-major axis (average distance from the Sun) in astronomical units (AU)
Solving for the distance (a):
1. We know P = 50 years
2. Substitute P into the equation: 50² = a³
3. Simplify: 2500 = a³
4. Solve for a (take the cube root of both sides): a = ³√2500 ≈ 13.57 AU
Therefore, the distance of Planet X from the Sun is approximately 13.57 astronomical units.
Important Note: This calculation assumes a circular orbit for simplicity. Real planetary orbits are slightly elliptical, but this gives you a good approximation.