$$\lambda = \frac{c}{f}$$
where:
- \(\lambda\) is the wavelength in meters (m)
- \(c\) is the speed of light in a vacuum \((\approx 3\times10^8 \text{ m/s})\)
- \(f\) is the frequency in Hertz (Hz)
Given the frequency of 6.42 × 10^14 Hz, we can calculate the wavelength as follows:
$$\lambda = \frac{3\times10^8 \text{ m/s}}{6.42 \times 10^{14} \text{ Hz}} \approx 4.67 \times 10^{-7}\text{ m}$$
Therefore, the wavelength of the light with a frequency of 6.42 × 10^14 Hz is approximately 4.67 × 10^{-7} meters. This light falls into the visible range of the electromagnetic spectrum and is perceived as a deep red color.
